Diagram with respect to Ω_F and I on the radial coordinate, r. The orange surface indicates ﹩{\tilde{B}}^{2}-{\tilde{E}}^{2}=0﹩. The surface has symmetry with respect to the I = 0 plane. The region covered by the surface including the line I = 0, Ω_F = 0, r ≤ 2M shows the forbidden region of I and Ω_F because of ﹩{\tilde{B}}^{2}-{\tilde{E}}^{2}\lt 0﹩, which plays an important role driving finite I and Ω_F. The blue plane shows the possible steady state, including the stretched horizon. This clearly shows that the steady state should be ﹩I\lt 0﹩, because the surface with ﹩I\gt 0﹩ contains the region ﹩{\tilde{B}}^{2}-{\tilde{E}}^{2}=0﹩ except for the horizon. In such a case, we have ﹩P\gt 0﹩ when ﹩{{\rm{\Omega }}}_{{\rm{F}}}\gt 0﹩.